What is the general solution for 4sin^2(x)-2=0,0<= x<= 2pi ?

The general solution for 4sin^2(x)-2=0,0<= x<= 2pi is x= pi/4 ,x=(3pi)/4 ,x=(5pi)/4 ,x=(7pi)/4

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4sin^2(x)-2=0,0<= x<= 2pi

4 sin^{2} (x) - 2 = 0, 0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{3 π}{4}, x = \frac{5 π}{4}, x = \frac{7 π}{4}

Solution steps

4 sin^{2} (x) - 2 = 0, 0 \leq x \leq 2 π

Solve by substitution

sin (x) = \frac{1}{2}, sin (x) = - \frac{1}{2}

sin (x) = \frac{1}{2}, 0 \leq x \leq 2 π : x = \frac{π}{4}, x = \frac{3 π}{4}

sin (x) = - \frac{1}{2}, 0 \leq x \leq 2 π : x = \frac{5 π}{4}, x = \frac{7 π}{4}

Combine all the solutions

x = \frac{π}{4}, x = \frac{3 π}{4}, x = \frac{5 π}{4}, x = \frac{7 π}{4}

csc^{2} (θ) = 7 cot (θ) + 9

cos^{2} (x) + 6 cos (x) = - 3, y = 3

2 sec^{2} (x) - 5 tan (x) = 5

coth (z) = 1

cos (10 x) = sin (5 x - 3)

What is the general solution for 4sin^2(x)-2=0,0<= x<= 2pi ?
The general solution for 4sin^2(x)-2=0,0<= x<= 2pi is x= pi/4 ,x=(3pi)/4 ,x=(5pi)/4 ,x=(7pi)/4