What is the general solution for 1-tan^2(x)=(cos^2(x))/(cos^2(x)) ?

The general solution for 1-tan^2(x)=(cos^2(x))/(cos^2(x)) is x=pin

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1-tan^2(x)=(cos^2(x))/(cos^2(x))

1 - tan^{2} (x) = \frac{cos ^{2} ( x )}{cos ^{2} ( x )}

x = πn

Solution steps

1 - tan^{2} (x) = \frac{cos ^{2} ( x )}{cos ^{2} ( x )}

\frac{cos ^{2} ( x )}{cos ^{2} ( x )} = 1

1 - tan^{2} (x) = 1

Move

1

to the right side

- tan^{2} (x) = 0

Divide both sides by

- 1

tan (x) = 0

General solutions for

tan (x) = 0

x = 0 + πn

Solve

x = 0 + πn : x = πn

x = πn

- 2 = - 2 sec (x) + tan^{2} (x)

tan^{2} (y) + 1 = cos^{2} (y)

4 sin (2 x) + csc (2 x) = 4

cot (θ) = \frac{9}{40}

sin (a) = - \frac{1}{2}

What is the general solution for 1-tan^2(x)=(cos^2(x))/(cos^2(x)) ?
The general solution for 1-tan^2(x)=(cos^2(x))/(cos^2(x)) is x=pin