What is the general solution for solvefor a,sin(2a)+1=0.5 ?

The general solution for solvefor a,sin(2a)+1=0.5 is a=(7pi)/(12)+pin,a=(11pi)/(12)+pin

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solvefor a,sin(2a)+1=0.5

solve for

a, sin (2 a) + 1 = 0.5

a = \frac{7 π}{12} + πn, a = \frac{11 π}{12} + πn

Solution steps

sin (2 a) + 1 = 0.5

Move

1

to the right side

sin (2 a) = - 0.5

General solutions for

sin (2 a) = - 0.5

2 a = \frac{7 π}{6} + 2 πn, 2 a = \frac{11 π}{6} + 2 πn

Solve

2 a = \frac{7 π}{6} + 2 πn : a = \frac{7 π}{12} + πn

Solve

2 a = \frac{11 π}{6} + 2 πn : a = \frac{11 π}{12} + πn

a = \frac{7 π}{12} + πn, a = \frac{11 π}{12} + πn

\frac{( sin ( 5 x ) )}{( - 1 cos ( 5 x ) )} = 0

sin (x) = cos (4 0^{\circ})

tan (x) = \frac{2.5}{2}

sin (2 x) cos (x) + sin (x) cos (2 x) = - \frac{1}{2}

5 cos (x) + 2 = 3 cos (x), 0 \leq x \leq 2 π

What is the general solution for solvefor a,sin(2a)+1=0.5 ?
The general solution for solvefor a,sin(2a)+1=0.5 is a=(7pi)/(12)+pin,a=(11pi)/(12)+pin