What is the general solution for (sqrt(3))/3 =-1/3*tan(θ) ?

The general solution for (sqrt(3))/3 =-1/3*tan(θ) is θ=(2pi)/3+pin

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(sqrt(3))/3 =-1/3*tan(θ)

\frac{3}{3} = - \frac{1}{3} \cdot tan (θ)

θ = \frac{2 π}{3} + πn

Solution steps

\frac{3}{3} = - \frac{1}{3} tan (θ)

Switch sides

- \frac{1}{3} tan (θ) = \frac{3}{3}

Multiply both sides by

- 3

tan (θ) = - 3

General solutions for

tan (θ) = - 3

θ = \frac{2 π}{3} + πn

tan (x + \frac{π}{3}) = 3

16 sin^{2} (x) = 1

x, - 1 \cdot \frac{cos ( x )}{sin ( x )} = 0

8 cos (θ) - 4 = 0

2 (1 + cos (θ)) = 0

What is the general solution for (sqrt(3))/3 =-1/3*tan(θ) ?
The general solution for (sqrt(3))/3 =-1/3*tan(θ) is θ=(2pi)/3+pin