What is the general solution for sin(2x)=0.03 ?

The general solution for sin(2x)=0.03 is x=(0.03000…)/2+pin,x= pi/2-(0.03000…)/2+pin

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sin(2x)=0.03

sin (2 x) = 0.03

x = \frac{0.03000 \dots}{2} + πn, x = \frac{π}{2} - \frac{0.03000 \dots}{2} + πn

Solution steps

sin (2 x) = 0.03

Apply trig inverse properties

2 x = arcsin (0.03) + 2 πn, 2 x = π - arcsin (0.03) + 2 πn

Solve

2 x = arcsin (0.03) + 2 πn : x = \frac{arcsin ( 0.03 )}{2} + πn

Solve

2 x = π - arcsin (0.03) + 2 πn : x = \frac{π}{2} - \frac{arcsin ( 0.03 )}{2} + πn

x = \frac{arcsin ( 0.03 )}{2} + πn, x = \frac{π}{2} - \frac{arcsin ( 0.03 )}{2} + πn

Show solutions in decimal form

x = \frac{0.03000 \dots}{2} + πn, x = \frac{π}{2} - \frac{0.03000 \dots}{2} + πn

0 = - 3 + 2 sin (x)

cos (x) = \frac{( 35 )}{( 57 )}

x, sin^{2} (x) = 0.5

tan^{2} (x) - 3 tan (x) - 28 = 0

cot (x) = - 0.69

What is the general solution for sin(2x)=0.03 ?
The general solution for sin(2x)=0.03 is x=(0.03000…)/2+pin,x= pi/2-(0.03000…)/2+pin