What is the general solution for tan^2(x)-3tan(x)-28=0 ?

The general solution for tan^2(x)-3tan(x)-28=0 is x=1.42889…+pin,x=-1.32581…+pin

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tan^2(x)-3tan(x)-28=0

tan^{2} (x) - 3 tan (x) - 28 = 0

x = 1.42889 \dots + πn, x = - 1.32581 \dots + πn

Solution steps

tan^{2} (x) - 3 tan (x) - 28 = 0

Solve by substitution

tan (x) = 7, tan (x) = - 4

tan (x) = 7 : x = arctan (7) + πn

tan (x) = - 4 : x = arctan (- 4) + πn

Combine all the solutions

x = arctan (7) + πn, x = arctan (- 4) + πn

Show solutions in decimal form

x = 1.42889 \dots + πn, x = - 1.32581 \dots + πn

cot (x) = - 0.69

sin (θ) = - \frac{1}{8}

0 = 2 cos^{2} (θ) - cos (θ) - 1

sin (x) = \frac{3}{1.65}

tan (x) = - 2, tan (- x)

What is the general solution for tan^2(x)-3tan(x)-28=0 ?
The general solution for tan^2(x)-3tan(x)-28=0 is x=1.42889…+pin,x=-1.32581…+pin