What is the general solution for 0=2cos^2(θ)-cos(θ)-1 ?

The general solution for 0=2cos^2(θ)-cos(θ)-1 is θ=2pin,θ=(2pi)/3+2pin,θ=(4pi)/3+2pin

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0=2cos^2(θ)-cos(θ)-1

0 = 2 cos^{2} (θ) - cos (θ) - 1

θ = 2 πn, θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solution steps

0 = 2 cos^{2} (θ) - cos (θ) - 1

Switch sides

2 cos^{2} (θ) - cos (θ) - 1 = 0

Solve by substitution

cos (θ) = 1, cos (θ) = - \frac{1}{2}

cos (θ) = 1 : θ = 2 πn

cos (θ) = - \frac{1}{2} : θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Combine all the solutions

θ = 2 πn, θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

sin (x) = \frac{3}{1.65}

tan (x) = - 2, tan (- x)

x, y^{1} = y sin (x)

- 0.3 cos (θ) = cos (2.2 + θ)

2 cos^{4} (θ) + 9 sin^{2} (θ) = 5

What is the general solution for 0=2cos^2(θ)-cos(θ)-1 ?
The general solution for 0=2cos^2(θ)-cos(θ)-1 is θ=2pin,θ=(2pi)/3+2pin,θ=(4pi)/3+2pin