What is the general solution for solvefor x,y^1=ysin(x) ?

The general solution for solvefor x,y^1=ysin(x) is x= pi/2+2pin

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solvefor x,y^1=ysin(x)

solve for

x, y^{1} = y sin (x)

x = \frac{π}{2} + 2 πn

Solution steps

y^{1} = y sin (x)

Switch sides

y sin (x) = y^{1}

Apply rule

a^{1} = a

y sin (x) = y

Divide both sides by

y; y \neq = 0

sin (x) = 1; y \neq = 0

General solutions for

sin (x) = 1

x = \frac{π}{2} + 2 πn

- 0.3 cos (θ) = cos (2.2 + θ)

2 cos^{4} (θ) + 9 sin^{2} (θ) = 5

tan (3 x) = 2.5

sin (θ) = \frac{4}{5}, 0 < θ < \frac{π}{2}, cos (2)

25 (sec^{2} (5 x)) = 0

What is the general solution for solvefor x,y^1=ysin(x) ?
The general solution for solvefor x,y^1=ysin(x) is x= pi/2+2pin