What is the general solution for 2tan^2(θ)=2 ?

The general solution for 2tan^2(θ)=2 is θ= pi/4+pin,θ=(3pi)/4+pin

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2tan^2(θ)=2

2 tan^{2} (θ) = 2

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

Solution steps

2 tan^{2} (θ) = 2

Solve by substitution

tan (θ) = 1, tan (θ) = - 1

tan (θ) = 1 : θ = \frac{π}{4} + πn

tan (θ) = - 1 : θ = \frac{3 π}{4} + πn

Combine all the solutions

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

0 = (6 cos (30 t) + 2 sin (30 t))

- 2 sin (θ) = 2

tan (2 x - \frac{π}{6}) = \frac{1}{3 ^{\frac{1}{2}}}

sin^{2} (\frac{x}{2}) - 1 = 0

69 = cos (x)

What is the general solution for 2tan^2(θ)=2 ?
The general solution for 2tan^2(θ)=2 is θ= pi/4+pin,θ=(3pi)/4+pin