What is the general solution for sin^2(x/2)-1=0 ?

The general solution for sin^2(x/2)-1=0 is x=pi+4pin,x=3pi+4pin

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sin^2(x/2)-1=0

sin^{2} (\frac{x}{2}) - 1 = 0

x = π + 4 πn, x = 3 π + 4 πn

Solution steps

sin^{2} (\frac{x}{2}) - 1 = 0

Solve by substitution

sin (\frac{x}{2}) = 1, sin (\frac{x}{2}) = - 1

sin (\frac{x}{2}) = 1 : x = π + 4 πn

sin (\frac{x}{2}) = - 1 : x = 3 π + 4 πn

Combine all the solutions

x = π + 4 πn, x = 3 π + 4 πn

69 = cos (x)

sin^{2} (θ) = cos (θ) + cos^{2} (θ)

7 cos (θ) = 2 + 9 cos (θ)

sec (x) \cdot cot (x) - 2 cot (x) + sec (x) = 2

3 sin^{2} (x) - 10 sin (x) - 8 = 0

What is the general solution for sin^2(x/2)-1=0 ?
The general solution for sin^2(x/2)-1=0 is x=pi+4pin,x=3pi+4pin