What is the general solution for sin(pi/6-x)=1 ?

The general solution for sin(pi/6-x)=1 is x=-2pin-pi/3

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sin(pi/6-x)=1

Solution

sin (\frac{π}{6} - x) = 1

Solution

x = - 2 πn - \frac{π}{3}

Degrees

x = - 6 0^{\circ} - 36 0^{\circ} n

Solution steps

sin (\frac{π}{6} - x) = 1

General solutions for

sin (\frac{π}{6} - x) = 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

\frac{π}{6} - x = \frac{π}{2} + 2 πn

\frac{π}{6} - x = \frac{π}{2} + 2 πn

Solve

\frac{π}{6} - x = \frac{π}{2} + 2 πn : x = - 2 πn - \frac{π}{3}

\frac{π}{6} - x = \frac{π}{2} + 2 πn

Move

\frac{π}{6}

to the right side

\frac{π}{6} - x = \frac{π}{2} + 2 πn

Subtract

\frac{π}{6}

from both sides

\frac{π}{6} - x - \frac{π}{6} = \frac{π}{2} + 2 πn - \frac{π}{6}

Simplify

\frac{π}{6} - x - \frac{π}{6} = \frac{π}{2} + 2 πn - \frac{π}{6}

Simplify

\frac{π}{6} - x - \frac{π}{6} : - x

\frac{π}{6} - x - \frac{π}{6}

Add similar elements:

\frac{π}{6} - \frac{π}{6} = 0

= - x

Simplify

\frac{π}{2} + 2 πn - \frac{π}{6} : 2 πn + \frac{π}{3}

\frac{π}{2} + 2 πn - \frac{π}{6}

Group like terms

= 2 πn + \frac{π}{2} - \frac{π}{6}

Least Common Multiplier of

2, 6 : 6

2, 6

Least Common Multiplier (LCM)

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Prime factorization of

6 : 2 \cdot 3

6

6

divides by

26 = 3 \cdot 2

= 2 \cdot 3

2, 3

are all prime numbers, therefore no further factorization is possible

= 2 \cdot 3

Multiply each factor the greatest number of times it occurs in either

2

6

= 2 \cdot 3

Multiply the numbers:

2 \cdot 3 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

\frac{π}{2} :

multiply the denominator and numerator by

3

\frac{π}{2} = \frac{π 3}{2 \cdot 3} = \frac{π 3}{6}

= \frac{π 3}{6} - \frac{π}{6}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{π 3 - π}{6}

Add similar elements:

3 π - π = 2 π

= \frac{2 π}{6}

Cancel the common factor:

2

= 2 πn + \frac{π}{3}

- x = 2 πn + \frac{π}{3}

- x = 2 πn + \frac{π}{3}

- x = 2 πn + \frac{π}{3}

Divide both sides by

- 1

- x = 2 πn + \frac{π}{3}

Divide both sides by

- 1

\frac{- x}{- 1} = \frac{2 πn}{- 1} + \frac{\frac{π}{3}}{- 1}

Simplify

\frac{- x}{- 1} = \frac{2 πn}{- 1} + \frac{\frac{π}{3}}{- 1}

Simplify

\frac{- x}{- 1} : x

\frac{- x}{- 1}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{x}{1}

Apply rule

\frac{a}{1} = a

= x

Simplify

\frac{2 πn}{- 1} + \frac{\frac{π}{3}}{- 1} : - 2 πn - \frac{π}{3}

\frac{2 πn}{- 1} + \frac{\frac{π}{3}}{- 1}

\frac{2 πn}{- 1} = - 2 πn

\frac{2 πn}{- 1}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{2 πn}{1}

Apply rule

\frac{a}{1} = a

= - 2 πn

= - 2 πn + \frac{\frac{π}{3}}{- 1}

\frac{\frac{π}{3}}{- 1} = - \frac{π}{3}

\frac{\frac{π}{3}}{- 1}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{\frac{π}{3}}{1}

Apply the fraction rule:

\frac{a}{1} = a

\frac{\frac{π}{3}}{1} = \frac{π}{3}

= - \frac{π}{3}

= - 2 πn - \frac{π}{3}

x = - 2 πn - \frac{π}{3}

x = - 2 πn - \frac{π}{3}

x = - 2 πn - \frac{π}{3}

x = - 2 πn - \frac{π}{3}

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Frequently Asked Questions (FAQ)

What is the general solution for sin(pi/6-x)=1 ?
The general solution for sin(pi/6-x)=1 is x=-2pin-pi/3