What is the general solution for (sin(x^3+2x-1))a=1 ?

The general solution for (sin(x^3+2x-1))a=1 is No Solution for x\in\mathbb{R}

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(sin(x^3+2x-1))a=1

(sin (x^{3} + 2 x - 1)) a = 1

No Solution for x \in R

Solution steps

(sin (x^{3} + 2 x - 1)) a = 1

Divide both sides by

a; a \neq = 0

sin (x^{3} + 2 x - 1) = \frac{1}{a}; a \neq = 0

Apply trig inverse properties

x^{3} + 2 x - 1 = arcsin (\frac{1}{a}) + 2 πn, x^{3} + 2 x - 1 = π + arcsin (- \frac{1}{a}) + 2 πn

No Solution for x \in R

cos (θ) = - \frac{7}{10}

cot (b) = \frac{tan ( b ) cot ( b )}{csc ( b )}

h, f = tan (x) tan (h) x

cos (x) + 2 sin (x) + 3 = 0

x, arccos (x) = 1

What is the general solution for (sin(x^3+2x-1))a=1 ?
The general solution for (sin(x^3+2x-1))a=1 is No Solution for x\in\mathbb{R}