What is the general solution for cos(2x)= 1/2 ,(0,2pi) ?

The general solution for cos(2x)= 1/2 ,(0,2pi) is x= pi/6 ,x=(5pi)/6 ,x=(7pi)/6 ,x=(11pi)/6

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cos(2x)= 1/2 ,(0,2pi)

cos (2 x) = \frac{1}{2}, (0, 2 π)

x = \frac{π}{6}, x = \frac{5 π}{6}, x = \frac{7 π}{6}, x = \frac{11 π}{6}

Solution steps

cos (2 x) = \frac{1}{2}, (0, 2 π)

General solutions for

cos (2 x) = \frac{1}{2}

2 x = \frac{π}{3} + 2 πn, 2 x = \frac{5 π}{3} + 2 πn

Solve

2 x = \frac{π}{3} + 2 πn : x = \frac{π}{6} + πn

Solve

2 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{6} + πn

x = \frac{π}{6} + πn, x = \frac{5 π}{6} + πn

Solutions for the range

(0, 2 π)

x = \frac{π}{6}, x = \frac{5 π}{6}, x = \frac{7 π}{6}, x = \frac{11 π}{6}

3 sec (x) = 6

6 = 6 sin (2 π (47) t), 0 < t < 0.0212

c = \frac{1}{sec ( x ) + tan ( x )} + \frac{1}{sec ( x ) - tan ( x )}

0.25 \cdot cos (x) = - 0.249

cos (x) sin (x) cos (x) = 1 - sin^{2} (x)

What is the general solution for cos(2x)= 1/2 ,(0,2pi) ?
The general solution for cos(2x)= 1/2 ,(0,2pi) is x= pi/6 ,x=(5pi)/6 ,x=(7pi)/6 ,x=(11pi)/6