What is the general solution for 6cos(2t)=0 ?

The general solution for 6cos(2t)=0 is t= pi/4+pin,t=(3pi)/4+pin

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6cos(2t)=0

6 cos (2 t) = 0

t = \frac{π}{4} + πn, t = \frac{3 π}{4} + πn

Solution steps

6 cos (2 t) = 0

Divide both sides by

6

cos (2 t) = 0

General solutions for

cos (2 t) = 0

2 t = \frac{π}{2} + 2 πn, 2 t = \frac{3 π}{2} + 2 πn

Solve

2 t = \frac{π}{2} + 2 πn : t = \frac{π}{4} + πn

Solve

2 t = \frac{3 π}{2} + 2 πn : t = \frac{3 π}{4} + πn

t = \frac{π}{4} + πn, t = \frac{3 π}{4} + πn

2 cos^{2} (t) - 3 cos (t) = - 1, 0 \leq t \leq 2 π

4 cos (4 x) = 3

tan (y) = - 2

sin (θ) = - \frac{2}{2}

sin^{2} (x) + sin (x) \cdot cos (x) + cos^{2} (x) = 10

What is the general solution for 6cos(2t)=0 ?
The general solution for 6cos(2t)=0 is t= pi/4+pin,t=(3pi)/4+pin