What is the general solution for sin(4x)=cos(4x) ?

The general solution for sin(4x)=cos(4x) is x= pi/(16)+(pin)/4

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sin(4x)=cos(4x)

sin (4 x) = cos (4 x)

x = \frac{π}{16} + \frac{πn}{4}

Solution steps

sin (4 x) = cos (4 x)

Rewrite using trig identities

tan (4 x) = 1

General solutions for

tan (4 x) = 1

4 x = \frac{π}{4} + πn

Solve

4 x = \frac{π}{4} + πn : x = \frac{π}{16} + \frac{πn}{4}

x = \frac{π}{16} + \frac{πn}{4}

2 cos^{2} (x) + 9 cos (x) + 4 = 0

x, arccsc (2 x) = \frac{π}{6}

sin^{2} (x) + tan^{2} (x) = 1

cos (6 x) = sin (x - 1)

tan (θ) = \frac{72}{65}

What is the general solution for sin(4x)=cos(4x) ?
The general solution for sin(4x)=cos(4x) is x= pi/(16)+(pin)/4