What is the general solution for 3-tan^2(b)=0 ?

The general solution for 3-tan^2(b)=0 is b= pi/3+pin,b=(2pi)/3+pin

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3-tan^2(b)=0

3 - tan^{2} (b) = 0

b = \frac{π}{3} + πn, b = \frac{2 π}{3} + πn

Solution steps

3 - tan^{2} (b) = 0

Solve by substitution

tan (b) = 3, tan (b) = - 3

tan (b) = 3 : b = \frac{π}{3} + πn

tan (b) = - 3 : b = \frac{2 π}{3} + πn

Combine all the solutions

b = \frac{π}{3} + πn, b = \frac{2 π}{3} + πn

\frac{( 2 sin ( x ) ) ( sin ( x ) )}{sin ( x )} + 1 = 3

tan (2 θ) = - \frac{2}{5}

cos (2 x) - 3 cos (x) = - 2

3 cos (x) - 3 sin (x) = 0

cos^{2} (3 x) = cos (9 x^{2})

What is the general solution for 3-tan^2(b)=0 ?
The general solution for 3-tan^2(b)=0 is b= pi/3+pin,b=(2pi)/3+pin