What is the general solution for solvefor t,0=(1.8)cos(2pift) ?

The general solution for solvefor t,0=(1.8)cos(2pift) is t= 1/(4f)+n/f ,t= 3/(4f)+n/f ;\quad f\ne 0

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solvefor t,0=(1.8)cos(2pift)

solve for

t, 0 = (1.8) cos (2 π f t)

t = \frac{1}{4 f} + \frac{n}{f}, t = \frac{3}{4 f} + \frac{n}{f}; f \neq = 0

Solution steps

0 = (1.8) cos (2 π f t)

Switch sides

1.8 cos (2 π f t) = 0

Multiply both sides by

10

18 cos (2 π f t) = 0

Divide both sides by

18

cos (2 π f t) = 0

General solutions for

cos (2 π f t) = 0

2 π f t = \frac{π}{2} + 2 πn, 2 π f t = \frac{3 π}{2} + 2 πn

Solve

2 π f t = \frac{π}{2} + 2 πn : t = \frac{1}{4 f} + \frac{n}{f}; f \neq = 0

Solve

2 π f t = \frac{3 π}{2} + 2 πn : t = \frac{3}{4 f} + \frac{n}{f}; f \neq = 0

t = \frac{1}{4 f} + \frac{n}{f}, t = \frac{3}{4 f} + \frac{n}{f}; f \neq = 0

2 cot (x) cos (x) + 2 cos (x) = cot (x) + 1

tan (θ) - 7 = - 12 cot (θ)

2 \cdot sin^{2} (x) - sin (x) = 1

4 cos^{2} (3 x) - 1 = 0

6 sin (b) + 12 = 0

What is the general solution for solvefor t,0=(1.8)cos(2pift) ?
The general solution for solvefor t,0=(1.8)cos(2pift) is t= 1/(4f)+n/f ,t= 3/(4f)+n/f ;\quad f\ne 0