What is the general solution for -2+sin(2θ)=-3/2 ?

The general solution for -2+sin(2θ)=-3/2 is θ= pi/(12)+pin,θ=(5pi)/(12)+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-2+sin(2θ)=-3/2

- 2 + sin (2 θ) = - \frac{3}{2}

θ = \frac{π}{12} + πn, θ = \frac{5 π}{12} + πn

Solution steps

- 2 + sin (2 θ) = - \frac{3}{2}

Move

2

to the right side

sin (2 θ) = \frac{1}{2}

General solutions for

sin (2 θ) = \frac{1}{2}

2 θ = \frac{π}{6} + 2 πn, 2 θ = \frac{5 π}{6} + 2 πn

Solve

2 θ = \frac{π}{6} + 2 πn : θ = \frac{π}{12} + πn

Solve

2 θ = \frac{5 π}{6} + 2 πn : θ = \frac{5 π}{12} + πn

θ = \frac{π}{12} + πn, θ = \frac{5 π}{12} + πn

tan (c) = \frac{24}{7}

sin (t) = \frac{- 1}{2}

sin (x + \frac{π}{6}) + cos (x + \frac{π}{3}) = cos (2 x)

24 sin (2 t) - 24 cos (t) = 0

8^{s i n^{2} (x)} = 4^{s i n (x) - \frac{1}{8}}

What is the general solution for -2+sin(2θ)=-3/2 ?
The general solution for -2+sin(2θ)=-3/2 is θ= pi/(12)+pin,θ=(5pi)/(12)+pin