What is the general solution for -2sin(θ/2)=0 ?

The general solution for -2sin(θ/2)=0 is θ=4pin,θ=2pi+4pin

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-2sin(θ/2)=0

- 2 sin (\frac{θ}{2}) = 0

θ = 4 πn, θ = 2 π + 4 πn

Solution steps

- 2 sin (\frac{θ}{2}) = 0

Divide both sides by

- 2

sin (\frac{θ}{2}) = 0

General solutions for

sin (\frac{θ}{2}) = 0

\frac{θ}{2} = 0 + 2 πn, \frac{θ}{2} = π + 2 πn

Solve

\frac{θ}{2} = 0 + 2 πn : θ = 4 πn

Solve

\frac{θ}{2} = π + 2 πn : θ = 2 π + 4 πn

θ = 4 πn, θ = 2 π + 4 πn

cos^{3} (θ) + cos^{2} (θ) - cos (θ) - 1 = 0

2 sin^{2} (x) - 2 sin (x) = 0

9 sin^{2} (x) - 6 sin (x) + 1 = 0

y, ln (x) = arctan (\frac{y}{x})

cos (a) + 1 = 4 cos (a) + 1

What is the general solution for -2sin(θ/2)=0 ?
The general solution for -2sin(θ/2)=0 is θ=4pin,θ=2pi+4pin