What is the general solution for 9=-9*sin(2x) ?

The general solution for 9=-9*sin(2x) is x=(3pi)/4+pin

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9=-9*sin(2x)

9 = - 9 \cdot sin (2 x)

x = \frac{3 π}{4} + πn

Solution steps

9 = - 9 sin (2 x)

Switch sides

- 9 sin (2 x) = 9

Divide both sides by

- 9

sin (2 x) = - 1

General solutions for

sin (2 x) = - 1

2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

2 sin (4 t) = 2 sin (4 t) cos (4 t)

a^{1} sin (x) = 43.1253

52800 = \frac{( 1500 ) ^{2} sin ( x )}{32.2}

7 cos (3 x) = 2, 0 \leq x < 2 π

6 cos (2 x) = 3

What is the general solution for 9=-9*sin(2x) ?
The general solution for 9=-9*sin(2x) is x=(3pi)/4+pin