What is the general solution for 1*sin(35)=1.33*sin(θ) ?

The general solution for 1*sin(35)=1.33*sin(θ) is θ=0.44588…+360n,θ=180-0.44588…+360n

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1sin(35)=1.33sin(θ)

1 \cdot sin (3 5^{\circ}) = 1.33 \cdot sin (θ)

θ = 0.44588 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.44588 \dots + 36 0^{\circ} n

Solution steps

1 \cdot sin (3 5^{\circ}) = 1.33 sin (θ)

Switch sides

1.33 sin (θ) = 1 \cdot sin (3 5^{\circ})

Multiply:

1 \cdot sin (3 5^{\circ}) = sin (3 5^{\circ})

1.33 sin (θ) = sin (3 5^{\circ})

Divide both sides by

1.33

sin (θ) = \frac{sin ( 3 5 ^{\circ} )}{1.33}

Apply trig inverse properties

θ = arcsin (\frac{sin ( 3 5 ^{\circ} )}{1.33}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{sin ( 3 5 ^{\circ} )}{1.33}) + 36 0^{\circ} n

Show solutions in decimal form

θ = 0.44588 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.44588 \dots + 36 0^{\circ} n

cos (3 A) = 1

cos (θ) = (- 0.68159)

cot (x + \frac{5 π}{6}) = 3

θ, y = sin (θ)

sec^{2} (x) - 4 tan^{2} (x) = 0

What is the general solution for 1*sin(35)=1.33*sin(θ) ?
The general solution for 1*sin(35)=1.33*sin(θ) is θ=0.44588…+360n,θ=180-0.44588…+360n