What is the general solution for 6sin(2x)-3=0 ?

The general solution for 6sin(2x)-3=0 is x= pi/(12)+pin,x=(5pi)/(12)+pin

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6sin(2x)-3=0

6 sin (2 x) - 3 = 0

x = \frac{π}{12} + πn, x = \frac{5 π}{12} + πn

Solution steps

6 sin (2 x) - 3 = 0

Move

3

to the right side

6 sin (2 x) = 3

Divide both sides by

6

sin (2 x) = \frac{1}{2}

General solutions for

sin (2 x) = \frac{1}{2}

2 x = \frac{π}{6} + 2 πn, 2 x = \frac{5 π}{6} + 2 πn

Solve

2 x = \frac{π}{6} + 2 πn : x = \frac{π}{12} + πn

Solve

2 x = \frac{5 π}{6} + 2 πn : x = \frac{5 π}{12} + πn

x = \frac{π}{12} + πn, x = \frac{5 π}{12} + πn

4 cos^{2} (x) - sin (x) = 1

0.6 = cos (4 x)

sin (x) = \frac{1}{1.33}

- 3 = cos (0 + C)

cos (θ) + 3 sin (\frac{θ}{2}) - 2 = 0

What is the general solution for 6sin(2x)-3=0 ?
The general solution for 6sin(2x)-3=0 is x= pi/(12)+pin,x=(5pi)/(12)+pin