What is the general solution for sin(x)= 1/(1.33) ?

The general solution for sin(x)= 1/(1.33) is x=0.85090…+2pin,x=pi-0.85090…+2pin

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sin(x)= 1/(1.33)

sin (x) = \frac{1}{1.33}

x = 0.85090 \dots + 2 πn, x = π - 0.85090 \dots + 2 πn

Solution steps

sin (x) = \frac{1}{1.33}

Apply trig inverse properties

x = arcsin (\frac{1}{1.33}) + 2 πn, x = π - arcsin (\frac{1}{1.33}) + 2 πn

Show solutions in decimal form

x = 0.85090 \dots + 2 πn, x = π - 0.85090 \dots + 2 πn

- 3 = cos (0 + C)

cos (θ) + 3 sin (\frac{θ}{2}) - 2 = 0

2 sec (θ) = 6

sin (2 x + 20) - 1 = \frac{- 1}{2}

x, sin (x + \frac{π}{2}) - cos^{2} (x) = 0

What is the general solution for sin(x)= 1/(1.33) ?
The general solution for sin(x)= 1/(1.33) is x=0.85090…+2pin,x=pi-0.85090…+2pin