What is the general solution for arccosh(x)=1 ?

The general solution for arccosh(x)=1 is No Solution for x\in\mathbb{R}

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Popular >

arccosh(x)=1

Solution

arccosh (x) = 1

Solution

No Solution for x \in R

Solution steps

arccosh (x) = 1

Subtract

1

from both sides

arccosh (x) - 1 = 0

Solve by substitution

arccosh (x) - 1 = 0

Let:

arccosh (x) = u

u - 1 = 0

u - 1 = 0 : u = 1

u - 1 = 0

Move

1

to the right side

u - 1 = 0

Add

1

to both sides

u - 1 + 1 = 0 + 1

Simplify

u = 1

u = 1

Substitute back

u = arccosh (x)

arccosh (x) = 1

arccosh (x) = 1

Rewrite using trig identities

- 1 + arccosh (x)

Use the Hyperbolic identity:

arccosh (x) = ln (x + x^{2} - 1)

= - 1 + ln (x + x^{2} - 1)

- 1 + ln (- 1 + x^{2} + x) = 0

Move

1

to the right side

- 1 + ln (- 1 + x^{2} + x) = 0

Add

1

to both sides

- 1 + ln (- 1 + x^{2} + x) + 1 = 0 + 1

Simplify

ln (- 1 + x^{2} + x) = 1

ln (- 1 + x^{2} + x) = 1

Apply trig inverse properties

ln (- 1 + x^{2} + x) = 1

General solutions for

ln (- 1 + x^{2} + x) = 1

Solve

No Solution for

x \in R

Remove square roots

Subtract

x

from both sides

Simplify

- 1 + x^{2} = Undefined

Square both sides:

- 1 + x^{2} =

Undefined

^{2}

(- 1 + x^{2})^{2} = Undefined^{2}

Expand

(- 1 + x^{2})^{2} : - 1 + x^{2}

(- 1 + x^{2})^{2}

Apply radical rule:

a = a^{\frac{1}{2}}

= ((- 1 + x^{2})^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= (- 1 + x^{2})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= - 1 + x^{2}

- 1 + x^{2} = Undefined^{2}

- 1 + x^{2} = Undefined^{2}

- 1 + x^{2} = Undefined^{2}

Solve

- 1 + x^{2} =

Undefined

^{2} :

No Solution for

x \in R

- 1 + x^{2} = Undefined^{2}

Move

1

to the right side

- 1 + x^{2} = Undefined^{2}

Add

1

to both sides

- 1 + x^{2} + 1 = Undefined^{2} + 1

Simplify

x^{2} = Undefined^{2} + 1

x^{2} = Undefined^{2} + 1

Therefore

No Solution for x \in R

No Solution for x \in R

Solve

No Solution for

x \in R

Remove square roots

Subtract

x

from both sides

Simplify

- 1 + x^{2} = Undefined

Square both sides:

- 1 + x^{2} =

Undefined

^{2}

(- 1 + x^{2})^{2} = Undefined^{2}

Expand

(- 1 + x^{2})^{2} : - 1 + x^{2}

(- 1 + x^{2})^{2}

Apply radical rule:

a = a^{\frac{1}{2}}

= ((- 1 + x^{2})^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= (- 1 + x^{2})^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= - 1 + x^{2}

- 1 + x^{2} = Undefined^{2}

- 1 + x^{2} = Undefined^{2}

- 1 + x^{2} = Undefined^{2}

Solve

- 1 + x^{2} =

Undefined

^{2} :

No Solution for

x \in R

- 1 + x^{2} = Undefined^{2}

Move

1

to the right side

- 1 + x^{2} = Undefined^{2}

Add

1

to both sides

- 1 + x^{2} + 1 = Undefined^{2} + 1

Simplify

x^{2} = Undefined^{2} + 1

x^{2} = Undefined^{2} + 1

Therefore

No Solution for x \in R

No Solution for x \in R

No Solution for x \in R

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Frequently Asked Questions (FAQ)

What is the general solution for arccosh(x)=1 ?
The general solution for arccosh(x)=1 is No Solution for x\in\mathbb{R}