What is the general solution for 2/pi arccos(m*1-1)=0 ?

The general solution for 2/pi arccos(m*1-1)=0 is m=2

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2/pi arccos(m*1-1)=0

\frac{2}{π} arccos (m \cdot 1 - 1) = 0

m = 2

Solution steps

\frac{2}{π} arccos (m \cdot 1 - 1) = 0

Multiply both sides by

π

2 arccos (m 1 - 1) = 0

Divide both sides by

2

arccos (m 1 - 1) = 0

Apply trig inverse properties

m \cdot 1 - 1 = 1

Solve

m \cdot 1 - 1 = 1 : m = 2

m = 2

sin (θ) cos (θ) - \frac{1}{2} cos (θ) = 0

cos^{2} (60) + cos^{2} (45) + cos^{2} (x) = 1

3 sin (5 x) = - 1, x < 2 π, 0

3 cos (x) + cos (3 x) = 0

sin^{2} (a) = 2 sin (a) cos (a)

What is the general solution for 2/pi arccos(m*1-1)=0 ?
The general solution for 2/pi arccos(m*1-1)=0 is m=2