What is the general solution for -6sin(θ)=-3sqrt(2) ?

The general solution for -6sin(θ)=-3sqrt(2) is θ= pi/4+2pin,θ=(3pi)/4+2pin

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-6sin(θ)=-3sqrt(2)

- 6 sin (θ) = - 32

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

Solution steps

- 6 sin (θ) = - 32

Divide both sides by

- 6

sin (θ) = \frac{2}{2}

General solutions for

sin (θ) = \frac{2}{2}

θ = \frac{π}{4} + 2 πn, θ = \frac{3 π}{4} + 2 πn

cos (x) = \frac{4 ( \frac{1}{2} ) - 1}{3}

sin (x) = \frac{π}{4} + \frac{0 π}{2}

cos (2 x) - sin (x) - 1 = 0

cos (x) = \frac{5}{20}

cos^{2} (x) + sin^{2} (x) = 2

What is the general solution for -6sin(θ)=-3sqrt(2) ?
The general solution for -6sin(θ)=-3sqrt(2) is θ= pi/4+2pin,θ=(3pi)/4+2pin