What is the general solution for solvefor y,-1/2 cot(y)=(t^2)/(+2)+C ?

The general solution for solvefor y,-1/2 cot(y)=(t^2)/(+2)+C is y=arccot(-t^2-2C)+pin

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solvefor y,-1/2 cot(y)=(t^2)/(+2)+C

solve for

y, - \frac{1}{2} cot (y) = \frac{t ^{2}}{+ 2} + C

y = arccot (- t^{2} - 2 C) + πn

Solution steps

- \frac{1}{2} cot (y) = \frac{t ^{2}}{2} + C

Multiply both sides by

- 2

cot (y) = - t^{2} - 2 C

Apply trig inverse properties

y = arccot (- t^{2} - 2 C) + πn

3 sec (2 θ) + 2 = 0

4 sin^{2} (x) + 1 = - 4 sin (x)

cos (3 x + 6 0^{\circ}) = 0

2 sin^{2} (x) + (- 2 - 2) sin (x) + 2 = 0

3 - 3 tan (2 x) = 4 - 23 tan (2 x)

What is the general solution for solvefor y,-1/2 cot(y)=(t^2)/(+2)+C ?
The general solution for solvefor y,-1/2 cot(y)=(t^2)/(+2)+C is y=arccot(-t^2-2C)+pin