What is the general solution for solvefor x,-ysin(x)=0 ?

The general solution for solvefor x,-ysin(x)=0 is x=2pin,x=pi+2pin

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solvefor x,-ysin(x)=0

solve for

x, - y sin (x) = 0

x = 2 πn, x = π + 2 πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

- y sin (x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

sin (x) = 0

General solutions for

sin (x) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

2 sin (\frac{x}{2} + \frac{π}{3}) = 3

x, 4 sin^{4} (x) - 8 sin^{2} (x) + 3 = 0

3 + 3 sin (θ) = 3 - 3 sin (θ)

\frac{sin ( C )}{18} = \frac{sin ( 6 3 ^{\circ} )}{17}

cos (\frac{1}{2} x) = - 1

What is the general solution for solvefor x,-ysin(x)=0 ?
The general solution for solvefor x,-ysin(x)=0 is x=2pin,x=pi+2pin