What is the general solution for 3+3sin(θ)=3-3sin(θ) ?

The general solution for 3+3sin(θ)=3-3sin(θ) is θ=2pin,θ=pi+2pin

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3+3sin(θ)=3-3sin(θ)

3 + 3 sin (θ) = 3 - 3 sin (θ)

θ = 2 πn, θ = π + 2 πn

Solution steps

3 + 3 sin (θ) = 3 - 3 sin (θ)

Solve by substitution

sin (θ) = 0

sin (θ) = 0 : θ = 2 πn, θ = π + 2 πn

Combine all the solutions

θ = 2 πn, θ = π + 2 πn

\frac{sin ( C )}{18} = \frac{sin ( 6 3 ^{\circ} )}{17}

cos (\frac{1}{2} x) = - 1

\frac{- ( 3 \cdot cos ( Q ^{1} ) )}{2} = 0

tan^{2} (x) + 3 tan (x) = 0, 0^{\circ} \leq x < 36 0^{\circ}

\frac{1}{2} (6.50941) + cos (θ) (10.40478) = 12

What is the general solution for 3+3sin(θ)=3-3sin(θ) ?
The general solution for 3+3sin(θ)=3-3sin(θ) is θ=2pin,θ=pi+2pin