What is the general solution for (-(3*cos(Q^1)))/2 =0 ?

The general solution for (-(3*cos(Q^1)))/2 =0 is Q= pi/2+2pin,Q=(3pi)/2+2pin

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(-(3*cos(Q^1)))/2 =0

\frac{- ( 3 \cdot cos ( Q ^{1} ) )}{2} = 0

Q = \frac{π}{2} + 2 πn, Q = \frac{3 π}{2} + 2 πn

Solution steps

\frac{- ( 3 cos ( Q ^{1} ) )}{2} = 0

Multiply both sides by

2

- 3 cos (Q^{1}) = 0

Divide both sides by

- 3

cos (Q^{1}) = 0

General solutions for

cos (Q^{1}) = 0

Q^{1} = \frac{π}{2} + 2 πn, Q^{1} = \frac{3 π}{2} + 2 πn

Solve

Q^{1} = \frac{π}{2} + 2 πn : Q = \frac{π}{2} + 2 πn

Solve

Q^{1} = \frac{3 π}{2} + 2 πn : Q = \frac{3 π}{2} + 2 πn

Q = \frac{π}{2} + 2 πn, Q = \frac{3 π}{2} + 2 πn

tan^{2} (x) + 3 tan (x) = 0, 0^{\circ} \leq x < 36 0^{\circ}

\frac{1}{2} (6.50941) + cos (θ) (10.40478) = 12

- 8 = - 4 + 4 tan (θ)

cos (x) = 0.2588

2 tan^{2} (x) + 3 tan (x) + 1 = 0

What is the general solution for (-(3*cos(Q^1)))/2 =0 ?
The general solution for (-(3*cos(Q^1)))/2 =0 is Q= pi/2+2pin,Q=(3pi)/2+2pin