en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan^2(x)+sqrt(3)tan(x)=0,0<= x<360

Solution

tan^{2} (x) + 3 tan (x) = 0, 0^{\circ} \leq x < 36 0^{\circ}

Solution

x = 0, x = 18 0^{\circ}, x = 12 0^{\circ}, x = 30 0^{\circ}

+1

Solution steps

tan^{2} (x) + 3 tan (x) = 0, 0^{\circ} \leq x < 36 0^{\circ}

Solve by substitution

tan (x) = 0, tan (x) = - 3

tan (x) = 0, 0 \leq x < 36 0^{\circ} : x = 0, x = 18 0^{\circ}

tan (x) = - 3, 0 \leq x < 36 0^{\circ} : x = 12 0^{\circ}, x = 30 0^{\circ}

Combine all the solutions

x = 0, x = 18 0^{\circ}, x = 12 0^{\circ}, x = 30 0^{\circ}

Popular Examples

1/2 (6.50941)+cos(θ)(10.40478)=12

\frac{1}{2} (6.50941) + cos (θ) (10.40478) = 12

- 8 = - 4 + 4 tan (θ)

cos (x) = 0.2588

2tan^2(x)+3tan(x)+1=0

2 tan^{2} (x) + 3 tan (x) + 1 = 0

-arctan(t)=(4-pi)/4

- arctan (t) = \frac{4 - π}{4}

Frequently Asked Questions (FAQ)

What is the general solution for tan^2(x)+sqrt(3)tan(x)=0,0<= x<360 ?
The general solution for tan^2(x)+sqrt(3)tan(x)=0,0<= x<360 is x=0,x=180,x=120,x=300