What is the general solution for sqrt(2)-cos(θ)=sqrt(2)+sin(θ) ?

The general solution for sqrt(2)-cos(θ)=sqrt(2)+sin(θ) is θ=(3pi)/4+pin

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sqrt(2)-cos(θ)=sqrt(2)+sin(θ)

2 - cos (θ) = 2 + sin (θ)

θ = \frac{3 π}{4} + πn

Solution steps

2 - cos (θ) = 2 + sin (θ)

Subtract

2 + sin (θ)

from both sides

- cos (θ) - sin (θ) = 0

Rewrite using trig identities

- 1 - tan (θ) = 0

Move

1

to the right side

- tan (θ) = 1

Divide both sides by

- 1

tan (θ) = - 1

General solutions for

tan (θ) = - 1

θ = \frac{3 π}{4} + πn

sin (x) = 6757

\frac{1}{cos ( x )} + tan (x) = 2

- 5 = - 5 + 4 sin (- 2 x + \frac{3 π}{4})

6 sec^{2} (x) + tan (x) - 9 = 0

3 tan^{2} (x) - cos^{2} (x) = sin^{2} (x)

What is the general solution for sqrt(2)-cos(θ)=sqrt(2)+sin(θ) ?
The general solution for sqrt(2)-cos(θ)=sqrt(2)+sin(θ) is θ=(3pi)/4+pin