What is the general solution for 1-cos(x)=(2sin^2(x))/2 ?

The general solution for 1-cos(x)=(2sin^2(x))/2 is x=2pin,x= pi/2+2pin,x=(3pi)/2+2pin

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1-cos(x)=(2sin^2(x))/2

1 - cos (x) = \frac{2 sin ^{2} ( x )}{2}

x = 2 πn, x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

1 - cos (x) = \frac{2 sin ^{2} ( x )}{2}

Subtract

\frac{2 sin ^{2} ( x )}{2}

from both sides

1 - cos (x) - sin^{2} (x) = 0

Rewrite using trig identities

- cos (x) + cos^{2} (x) = 0

Solve by substitution

cos (x) = 1, cos (x) = 0

cos (x) = 1 : x = 2 πn

cos (x) = 0 : x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = 2 πn, x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

2 sec (2 x) + tan (2 x) - 3 = 0

x, 5 = 9.4 cos (x)

20 = 2.891 sin (0.016 d - 1.183) + 18.512

2 sin (θ) = - 1, 0 \leq θ < 2 π

cos (16 x) = 0

What is the general solution for 1-cos(x)=(2sin^2(x))/2 ?
The general solution for 1-cos(x)=(2sin^2(x))/2 is x=2pin,x= pi/2+2pin,x=(3pi)/2+2pin