What is the general solution for cos(2x)cos(x)-sin(2x)sin(x)=0.5 ?

The general solution for cos(2x)cos(x)-sin(2x)sin(x)=0.5 is x= pi/9+(2pin)/3 ,x=(5pi)/9+(2pin)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(2x)cos(x)-sin(2x)sin(x)=0.5

cos (2 x) cos (x) - sin (2 x) sin (x) = 0.5

x = \frac{π}{9} + \frac{2 πn}{3}, x = \frac{5 π}{9} + \frac{2 πn}{3}

Solution steps

cos (2 x) cos (x) - sin (2 x) sin (x) = 0.5

Rewrite using trig identities

cos (2 x + x) = 0.5

General solutions for

cos (2 x + x) = 0.5

2 x + x = \frac{π}{3} + 2 πn, 2 x + x = \frac{5 π}{3} + 2 πn

Solve

2 x + x = \frac{π}{3} + 2 πn : x = \frac{π}{9} + \frac{2 πn}{3}

Solve

2 x + x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{9} + \frac{2 πn}{3}

x = \frac{π}{9} + \frac{2 πn}{3}, x = \frac{5 π}{9} + \frac{2 πn}{3}

sin^{2} (θ) = 0.4567

\frac{sin ( A )}{cos ( A )} - 2 = 1

cos (θ) = \frac{10}{15}

sin (θ) = \frac{40}{60}

10 = 3.44 sin (0.51 t + 4.11) + 9.48

What is the general solution for cos(2x)cos(x)-sin(2x)sin(x)=0.5 ?
The general solution for cos(2x)cos(x)-sin(2x)sin(x)=0.5 is x= pi/9+(2pin)/3 ,x=(5pi)/9+(2pin)/3