What is the general solution for 0=4sin(pi/2 (x-2))+2 ?

The general solution for 0=4sin(pi/2 (x-2))+2 is x=4n+13/3 ,x=4n+17/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0=4sin(pi/2 (x-2))+2

0 = 4 sin (\frac{π}{2} (x - 2)) + 2

x = 4 n + \frac{13}{3}, x = 4 n + \frac{17}{3}

Solution steps

0 = 4 sin (\frac{π}{2} (x - 2)) + 2

Switch sides

4 sin (\frac{π}{2} (x - 2)) + 2 = 0

Move

2

to the right side

4 sin (\frac{π}{2} (x - 2)) = - 2

Divide both sides by

4

sin (\frac{π}{2} (x - 2)) = - \frac{1}{2}

General solutions for

sin (\frac{π}{2} (x - 2)) = - \frac{1}{2}

\frac{π}{2} (x - 2) = \frac{7 π}{6} + 2 πn, \frac{π}{2} (x - 2) = \frac{11 π}{6} + 2 πn

Solve

\frac{π}{2} (x - 2) = \frac{7 π}{6} + 2 πn : x = 4 n + \frac{13}{3}

Solve

\frac{π}{2} (x - 2) = \frac{11 π}{6} + 2 πn : x = 4 n + \frac{17}{3}

x = 4 n + \frac{13}{3}, x = 4 n + \frac{17}{3}

sin (θ) = \frac{3}{8}, sin (2 0^{\circ})

- 2 sin (x) + 2 cos (x) = 0

cos (3 x) cos (9 x) + sin (3 x) sin (9 x) = 0, (0, 2 π)

1 + cot^{2} (x) + 2 csc (x) = 0

4 sin (2 x) = 3 sin (x)

What is the general solution for 0=4sin(pi/2 (x-2))+2 ?
The general solution for 0=4sin(pi/2 (x-2))+2 is x=4n+13/3 ,x=4n+17/3