What is the general solution for -2sin(x)+2cos(x)=0 ?

The general solution for -2sin(x)+2cos(x)=0 is x= pi/4+pin

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-2sin(x)+2cos(x)=0

- 2 sin (x) + 2 cos (x) = 0

x = \frac{π}{4} + πn

Solution steps

- 2 sin (x) + 2 cos (x) = 0

Rewrite using trig identities

- 2 tan (x) + 2 = 0

Move

2

to the right side

- 2 tan (x) = - 2

Divide both sides by

- 2

tan (x) = 1

General solutions for

tan (x) = 1

x = \frac{π}{4} + πn

cos (3 x) cos (9 x) + sin (3 x) sin (9 x) = 0, (0, 2 π)

1 + cot^{2} (x) + 2 csc (x) = 0

4 sin (2 x) = 3 sin (x)

sin (a) = 0.1245

x, sin (x + z) = cos (y + z)

What is the general solution for -2sin(x)+2cos(x)=0 ?
The general solution for -2sin(x)+2cos(x)=0 is x= pi/4+pin