What is the general solution for solvefor x,sin(x+z)=cos(y+z) ?

The general solution for solvefor x,sin(x+z)=cos(y+z) is x=-2z+2pin+pi/2-y,x=pi+2pin-pi/2+y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,sin(x+z)=cos(y+z)

solve for

x, sin (x + z) = cos (y + z)

x = - 2 z + 2 πn + \frac{π}{2} - y, x = π + 2 πn - \frac{π}{2} + y

Solution steps

sin (x + z) = cos (y + z)

Rewrite using trig identities

sin (x + z) = sin (\frac{π}{2} - (y + z))

Apply trig inverse properties

x + z = \frac{π}{2} - (y + z) + 2 πn, x + z = π - (\frac{π}{2} - (y + z)) + 2 πn

x + z = \frac{π}{2} - (y + z) + 2 πn : x = - 2 z + 2 πn + \frac{π}{2} - y

x + z = π - (\frac{π}{2} - (y + z)) + 2 πn : x = π + 2 πn - \frac{π}{2} + y

x = - 2 z + 2 πn + \frac{π}{2} - y, x = π + 2 πn - \frac{π}{2} + y

y, tan (y) = \frac{94}{152} c m

(sin (x) - 1) (sin (x) - 4) = 0

cos^{2} (a) = \frac{1}{5}

cos (2 9^{\circ} + θ) = 0.563

cot (θ) = \frac{18}{19}

What is the general solution for solvefor x,sin(x+z)=cos(y+z) ?
The general solution for solvefor x,sin(x+z)=cos(y+z) is x=-2z+2pin+pi/2-y,x=pi+2pin-pi/2+y