What is the general solution for (sin(x)-1)(sin(x)-4)=0 ?

The general solution for (sin(x)-1)(sin(x)-4)=0 is x= pi/2+2pin

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(sin(x)-1)(sin(x)-4)=0

(sin (x) - 1) (sin (x) - 4) = 0

x = \frac{π}{2} + 2 πn

Solution steps

(sin (x) - 1) (sin (x) - 4) = 0

Solving each part separately

sin (x) - 1 = 0 or sin (x) - 4 = 0

sin (x) - 1 = 0 : x = \frac{π}{2} + 2 πn

sin (x) - 4 = 0 :

No Solution

Combine all the solutions

x = \frac{π}{2} + 2 πn

cos^{2} (a) = \frac{1}{5}

cos (2 9^{\circ} + θ) = 0.563

cot (θ) = \frac{18}{19}

1 + cos (2 θ) = 3 sin (θ)

2 cos (x) sin (x) - 3 sin (x) = 0

What is the general solution for (sin(x)-1)(sin(x)-4)=0 ?
The general solution for (sin(x)-1)(sin(x)-4)=0 is x= pi/2+2pin