What is the general solution for cos(29+θ)=0.563 ?

The general solution for cos(29+θ)=0.563 is θ=0.97278…+360n-29,θ=360-0.97278…+360n-29

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cos(29+θ)=0.563

cos (2 9^{\circ} + θ) = 0.563

θ = 0.97278 \dots + 36 0^{\circ} n - 2 9^{\circ}, θ = 36 0^{\circ} - 0.97278 \dots + 36 0^{\circ} n - 2 9^{\circ}

Solution steps

cos (2 9^{\circ} + θ) = 0.563

Apply trig inverse properties

2 9^{\circ} + θ = arccos (0.563) + 36 0^{\circ} n, 2 9^{\circ} + θ = 36 0^{\circ} - arccos (0.563) + 36 0^{\circ} n

Solve

2 9^{\circ} + θ = arccos (0.563) + 36 0^{\circ} n : θ = arccos (0.563) + 36 0^{\circ} n - 2 9^{\circ}

Solve

2 9^{\circ} + θ = 36 0^{\circ} - arccos (0.563) + 36 0^{\circ} n : θ = 36 0^{\circ} - arccos (0.563) + 36 0^{\circ} n - 2 9^{\circ}

θ = arccos (0.563) + 36 0^{\circ} n - 2 9^{\circ}, θ = 36 0^{\circ} - arccos (0.563) + 36 0^{\circ} n - 2 9^{\circ}

Show solutions in decimal form

θ = 0.97278 \dots + 36 0^{\circ} n - 2 9^{\circ}, θ = 36 0^{\circ} - 0.97278 \dots + 36 0^{\circ} n - 2 9^{\circ}

cot (θ) = \frac{18}{19}

1 + cos (2 θ) = 3 sin (θ)

2 cos (x) sin (x) - 3 sin (x) = 0

cos (θ) - sin (θ) = cot (θ) cos (θ)

- 2 tan (x) + 1 + 2 tan^{2} (x) = tan^{2} (x)

What is the general solution for cos(29+θ)=0.563 ?
The general solution for cos(29+θ)=0.563 is θ=0.97278…+360n-29,θ=360-0.97278…+360n-29