What is the general solution for -2tan(x)+1+2tan^2(x)=tan^2(x) ?

The general solution for -2tan(x)+1+2tan^2(x)=tan^2(x) is x= pi/4+pin

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-2tan(x)+1+2tan^2(x)=tan^2(x)

- 2 tan (x) + 1 + 2 tan^{2} (x) = tan^{2} (x)

x = \frac{π}{4} + πn

Solution steps

- 2 tan (x) + 1 + 2 tan^{2} (x) = tan^{2} (x)

Solve by substitution

tan (x) = 1

tan (x) = 1 : x = \frac{π}{4} + πn

Combine all the solutions

x = \frac{π}{4} + πn

\frac{sin ( a )}{50} = \frac{sin ( 2 5 ^{\circ} )}{35}

sin (x + \frac{π}{4}) = \pm 1

sin (2 x + 64) = \frac{3}{2}

sin (θ) = 0, 6

sin (x) = sin (\frac{π}{2})

What is the general solution for -2tan(x)+1+2tan^2(x)=tan^2(x) ?
The general solution for -2tan(x)+1+2tan^2(x)=tan^2(x) is x= pi/4+pin