What is the general solution for 0=arctan(t) ?

The general solution for 0=arctan(t) is t=0

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0=arctan(t)

0 = arctan (t)

t = 0

Solution steps

0 = arctan (t)

Switch sides

arctan (t) = 0

Apply trig inverse properties

arctan (t) = 0

arctan (x) = a \Rightarrow x = tan (a)

t = tan (0)

tan (0) = 0

tan (0)

Use the following trivial identity:

tan (0) = 0

tan (0)

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

= 0

= 0

t = 0

t = 0

tan^{2} (x) = 1 + tan (x)

t, y = 3 sin (2 t - \frac{π}{4})

sec^{4} (x) = 0

sin (0.5 π) cos (0.5 π) = 0.5 sin (2 x + 1)

2 sin^{2} (u) = 1 + sin (u), 0 \leq y (u) < 2 π

What is the general solution for 0=arctan(t) ?
The general solution for 0=arctan(t) is t=0