What is the general solution for sin(B)= 1/(sqrt(3)) ?

The general solution for sin(B)= 1/(sqrt(3)) is B=0.61547…+2pin,B=pi-0.61547…+2pin

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sin(B)= 1/(sqrt(3))

sin (B) = \frac{1}{3}

B = 0.61547 \dots + 2 πn, B = π - 0.61547 \dots + 2 πn

Radians

B = 0.61547 \dots + 6.28318 \dots n, B = π - 0.61547 \dots + 6.28318 \dots n

Solution steps

sin (B) = \frac{1}{3}

Simplify

\frac{1}{3} : \frac{3}{3}

\frac{1}{3}

Multiply by the conjugate

\frac{3}{3}

= \frac{1 \cdot 3}{3 3}

1 \cdot 3 = 3

33 = 3

33

Apply radical rule:

a a = a

33 = 3

= 3

= \frac{3}{3}

sin (B) = \frac{3}{3}

Apply trig inverse properties

sin (B) = \frac{3}{3}

General solutions for

sin (B) = \frac{3}{3}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

B = arcsin (\frac{3}{3}) + 2 πn, B = π - arcsin (\frac{3}{3}) + 2 πn

B = arcsin (\frac{3}{3}) + 2 πn, B = π - arcsin (\frac{3}{3}) + 2 πn

Show solutions in decimal form

B = 0.61547 \dots + 2 πn, B = π - 0.61547 \dots + 2 πn

cos (7 x) = sin (5 x - 6)

100 = 211.49 - 20.96 cosh (0.03291765 x)

3 sec^{2} (x) + 4 cos^{2} (x) = 7

cos (θ) = \frac{43}{90}

8 cos (2 x - 5) = 3

What is the general solution for sin(B)= 1/(sqrt(3)) ?
The general solution for sin(B)= 1/(sqrt(3)) is B=0.61547…+2pin,B=pi-0.61547…+2pin