What is the general solution for 7sec(x)-7=0,0<= x<= 2pi ?

The general solution for 7sec(x)-7=0,0<= x<= 2pi is x=0,x=2pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7sec(x)-7=0,0<= x<= 2pi

7 sec (x) - 7 = 0, 0 \leq x \leq 2 π

x = 0, x = 2 π

Degrees

x = 0^{\circ}, x = 36 0^{\circ}

Solution steps

7 sec (x) - 7 = 0, 0 \leq x \leq 2 π

Move

7

to the right side

7 sec (x) - 7 = 0

Add

7

to both sides

7 sec (x) - 7 + 7 = 0 + 7

Simplify

7 sec (x) = 7

7 sec (x) = 7

Divide both sides by

7

7 sec (x) = 7

Divide both sides by

7

\frac{7 sec ( x )}{7} = \frac{7}{7}

Simplify

sec (x) = 1

sec (x) = 1

General solutions for

sec (x) = 1

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

x = 0 + 2 πn

x = 0 + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

Solutions for the range

0 \leq x \leq 2 π

x = 0, x = 2 π

cos (x) + cos (x) = cos (2 x)

csc^{2} (2 x - 0.6) = 16

tan (x - 1) = 2

5 sin^{2} (x) + 10 sin (x) + 2 = 0

tan (x) = \frac{5}{5.1}

What is the general solution for 7sec(x)-7=0,0<= x<= 2pi ?
The general solution for 7sec(x)-7=0,0<= x<= 2pi is x=0,x=2pi