What is the general solution for 8=8cos(3θ) ?

The general solution for 8=8cos(3θ) is θ=(2pin)/3

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8=8cos(3θ)

8 = 8 cos (3 θ)

θ = \frac{2 πn}{3}

Degrees

θ = 0^{\circ} + 12 0^{\circ} n

Solution steps

8 = 8 cos (3 θ)

Switch sides

8 cos (3 θ) = 8

Divide both sides by

8

8 cos (3 θ) = 8

Divide both sides by

8

\frac{8 cos ( 3 θ )}{8} = \frac{8}{8}

Simplify

cos (3 θ) = 1

cos (3 θ) = 1

General solutions for

cos (3 θ) = 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

3 θ = 0 + 2 πn

3 θ = 0 + 2 πn

Solve

3 θ = 0 + 2 πn : θ = \frac{2 πn}{3}

3 θ = 0 + 2 πn

0 + 2 πn = 2 πn

3 θ = 2 πn

Divide both sides by

3

3 θ = 2 πn

Divide both sides by

3

\frac{3 θ}{3} = \frac{2 πn}{3}

Simplify

θ = \frac{2 πn}{3}

θ = \frac{2 πn}{3}

θ = \frac{2 πn}{3}

sinh (2 x) = 0

cos^{2} (x) = \frac{1}{2} + \frac{1}{2} cos^{2} (x)

3 tan (x) = \frac{1}{cos ( x )}

cos (x) - sin (x) = 0, - π \leq x \leq π

5 - tan^{2} (x) = 4

What is the general solution for 8=8cos(3θ) ?
The general solution for 8=8cos(3θ) is θ=(2pin)/3