What is the general solution for -10sin(y)=0 ?

The general solution for -10sin(y)=0 is y=2pin,y=pi+2pin

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-10sin(y)=0

- 10 sin (y) = 0

y = 2 πn, y = π + 2 πn

Degrees

y = 0^{\circ} + 36 0^{\circ} n, y = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

- 10 sin (y) = 0

Divide both sides by

- 10

- 10 sin (y) = 0

Divide both sides by

- 10

\frac{- 10 sin ( y )}{- 10} = \frac{0}{- 10}

Simplify

sin (y) = 0

sin (y) = 0

General solutions for

sin (y) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

y = 0 + 2 πn, y = π + 2 πn

y = 0 + 2 πn, y = π + 2 πn

Solve

y = 0 + 2 πn : y = 2 πn

y = 0 + 2 πn

0 + 2 πn = 2 πn

y = 2 πn

y = 2 πn, y = π + 2 πn

4 cos^{2} (x) + 2 sin (x) = 3

sin (x) = sin (2 x), 0 \leq x \leq 2 π

\frac{1}{cos ( x )} = tan (x)

2 cos^{2} (x) - cos (x) - 1 = 0, (0, 2 π)

- 3 + cos (2 x) \cdot 2 = 0

What is the general solution for -10sin(y)=0 ?
The general solution for -10sin(y)=0 is y=2pin,y=pi+2pin