What is the value of sin(((3pi))/2) ?

The value of sin(((3pi))/2) is -1

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sin((3pi)/2)

sin (\frac{( 3 π )}{2})

- 1

Solution steps

sin (\frac{( 3 π )}{2})

= sin (\frac{3 π}{2})

Rewrite using trig identities:

sin (π) cos (\frac{π}{2}) + cos (π) sin (\frac{π}{2})

= sin (π) cos (\frac{π}{2}) + cos (π) sin (\frac{π}{2})

Use the following trivial identity:

sin (π) = 0

Use the following trivial identity:

cos (\frac{π}{2}) = 0

Use the following trivial identity:

cos (π) = (- 1)

Use the following trivial identity:

sin (\frac{π}{2}) = 1

= 0 \cdot 0 + (- 1) \cdot 1

Simplify

= - 1

x, k = \frac{( 1 + sin ( x ) )}{n}

a, tan (a) = \frac{1}{3}

cos (\frac{( 4 π )}{3})

cos (\frac{( 3 π )}{4})

sec (\frac{( 5 π )}{6})