What is the value of (cos(pi/4)+sin(pi/6))^2 ?

The value of (cos(pi/4)+sin(pi/6))^2 is (3+2sqrt(2))/4

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(cos(pi/4)+sin(pi/6))^2

(cos (\frac{π}{4}) + sin (\frac{π}{6}))^{2}

\frac{3 + 2 2}{4}

Solution steps

(cos (\frac{π}{4}) + sin (\frac{π}{6}))^{2}

Use the following trivial identity:

cos (\frac{π}{4}) = \frac{2}{2}

Use the following trivial identity:

sin (\frac{π}{6}) = \frac{1}{2}

= (\frac{2}{2} + \frac{1}{2})^{2}

Simplify

(\frac{2}{2} + \frac{1}{2})^{2} : \frac{3 + 2 2}{4}

= \frac{3 + 2 2}{4}

cos (94 5^{\circ})

cot (1 3^{\circ})

cos (arctan (- 5))

e^{c o s (π)} cos (π) - e^{c o s (π)} sin^{2} (π)

cos (6 0^{\circ} + 22 5^{\circ})

What is the value of (cos(pi/4)+sin(pi/6))^2 ?
The value of (cos(pi/4)+sin(pi/6))^2 is (3+2sqrt(2))/4