What is the value of 6/(tan(36)) ?

The value of 6/(tan(36)) is (3(5sqrt(2)+3sqrt(10))sqrt(5-\sqrt{5)})/(10)

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6/(tan(36))

\frac{6}{tan ( 3 6 ^{\circ} )}

\frac{3 ( 5 2 + 3 10 ) 5 - 5}{10}

Solution steps

\frac{6}{tan ( 3 6 ^{\circ} )}

Rewrite using trig identities:

tan (3 6^{\circ}) = \frac{2 ( 5 - 1 ) 5 - 5}{4}

= \frac{6}{\frac{2 ( 5 - 1 ) 5 - 5}{4}}

Simplify

\frac{6}{\frac{2 ( 5 - 1 ) 5 - 5}{4}} : \frac{3 ( 5 2 + 3 10 ) 5 - 5}{10}

= \frac{3 ( 5 2 + 3 10 ) 5 - 5}{10}

cos (\frac{( 2 π )}{3})

sin (arccos (0) - arccos (\frac{1}{2}))

10 tan (2 5^{\circ})

tan (3 0^{\circ} + 4 5^{\circ})

2 π cos (2 π)

What is the value of 6/(tan(36)) ?
The value of 6/(tan(36)) is (3(5sqrt(2)+3sqrt(10))sqrt(5-\sqrt{5)})/(10)