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radius (x-4)^2+(y+2)^2=25

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radius (x−4)²+(y+2)²=25

Solution

r=5

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(x−4)²+(y+2)²=25

Circle Equation

(x−a)²+(y−b)²=r² is the circle equation with a radius r, centered at (a, b)

Rewrite (x−4)²+(y+2)²=25 in the form of the standard circle equation

(x−4)²+(y−(−2))²=5²

Therefore the circle properties are:

(a, b)=(4, −2), r=5

And the radius is:

r=5

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

radius (x-4)^2+(y+2)^2=25

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