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foci ((x-1)^2)/9+(y^2)/5 =100

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foci (x−1)²9 +y²5 =100

Solution

(21, 0), (−19, 0)

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Ellipse Foci

For an ellipse with major axis parallel to the x-axis, the Foci (focus points) are defined as (h+c, k), (h−c, k),
where c=√a²−b² is the distance from the center (h, k) to a focus

(h+c, k), (h−c, k)

Calculate ellipse properties

(x−1)²9 +y²5 =100: Ellipse with center (h, k)=(1, 0), a=30, b=10√5

(1+c, 0), (1−c, 0)

Compute c:

c=√30²−(10√5)²: 20

(1+20, 0), (1−20, 0)

Refine

(21, 0), (−19, 0)

Ellipse Foci (Focus Points) Examples

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

foci ((x-1)^2)/9+(y^2)/5 =100

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